EconStatsCraft › Survival analysis

Survival analysis

The non-parametric Kaplan-Meier survival curve and Nelson-Aalen cumulative hazard with right-censoring, the median survival time, a log-rank test across an optional group, and fitted Exponential and Weibull models with AIC.

What it needs

The intuition

Some people have not had the event yet when the study ends, and throwing them away would be a disaster - they are the ones who lasted longest. Censoring is the whole problem survival analysis exists to solve. Kaplan-Meier handles it by working period by period: at each moment an event happens, ask what fraction of those still at risk survived it, and multiply those fractions together.

When to use it

Policy lapse and persistency analysis, mortality and morbidity studies, time to claim, equipment failure, or any duration data where following everyone to the event is impossible.

Where the estimator comes from

With distinct event times t_1<t_2<\dots, let d_j be the events at t_j and n_j the number still at risk just before. The Kaplan-Meier estimator is the product of conditional survivals, \hat{S}(t)=\prod_{t_j\le t}\left(1-\frac{d_j}{n_j}\right). A censored observation contributes to n_j up to its censoring time and then leaves the risk set without ever appearing in a d_j, which is exactly how it should count. Greenwood\'s formula gives the variance, \widehat{\mathrm{Var}}(\hat{S}(t))=\hat{S}(t)^2\sum_{t_j\le t}\frac{d_j}{n_j(n_j-d_j)}. The Cox model puts covariates on the hazard rather than the survival, h(t\mid x)=h_0(t)\exp(x'\beta), and estimates \beta from the partial likelihood without ever specifying h_0.

The model

\hat{S}(t) = \prod_{t_j \le t}\left(1 - \frac{d_j}{n_j}\right),\qquad \hat{H}(t) = \sum_{t_j \le t}\frac{d_j}{n_j}

What it assumes

Statistical properties

How to read the output

A worked reading

1,600 policies, 1,185 lapses and 415 still in force at the end - 25.9% censored, and every one of them carries information that dropping them would throw away. The Kaplan-Meier median survival time is 41.2. The estimate steps down only at observed event times (0.9496 at t = 7, 0.8817 at 12.3, 0.8143 at 16.9) and a censored observation leaves the risk set silently between steps, which is exactly how censoring is handled correctly rather than by guessing when those policies would have lapsed. The confidence band widens as the sample thins - ±0.011 at t = 7 against ±0.024 at t = 32.5 - because the tail of a survival curve rests on however few subjects remain. Two comparisons come free: a Weibull fit beats the exponential on AIC (11,714 against 11,869) with a shape of 1.396, so the hazard RISES with duration rather than staying flat; and the log-rank test separates the two channels decisively (chi-square 172.96, p < 0.0001), with broker business producing 613 lapses where 399 were expected.

Symptom → diagnosis → what to do

If you see thisIt meansDo this
Curve not reaching zeroThe longest observation was censoredReport the median, not the mean
A huge step late in the curveVery few still at riskThe tail is unreliable; show the at-risk table
Curves crossingNon-proportional hazardsThe log-rank test loses power; use a landmark or time-varying analysis
Median never reachedFewer than half had the eventQuote a different quantile, or restricted mean survival
Sicker subjects dropping outInformative censoringThe independence assumption fails; the estimate is optimistic
Confidence band leaving [0,1]The plain Greenwood interval on a raw scaleUse a log-log transformed interval

Common mistakes

Where to read this properly

See also

Life table, which is the same estimator on population data with grouped ages. Duration and hazard models in the time-series section.

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